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The JDK relies on hierarchical file systems to manage source and class files for Java programs, although The Java Language Specification does not require this. The strategy is as follows.You put the source code for a class or interface in a text file whose name is the short name of the class or interface and whose extension is
.java
(the JDK requires this extension for public classes and it's a good idea for other classes). Then, you put the source file in a directory whose name reflects the name of the package to which the class or interface belongs. For example, the source code for theRectangle
class would be in a file namedRectangle.java
and the file would be in a directory namedgraphics
. Thegraphics
directory may be anywhere on the file system. The following diagram shows how this works.The long name of the package member and the pathname to the file are parallel (assuming the UNIX filename separator slash / ): Furthermore, by convention, each company uses its reversed Internet domain name in its package names. (However, some companies now choose to drop "com" from their package names.) The fictional company called Taranis Interactive whose Internet domain name isgraphics.Rectangle class name graphics/Rectangle.java pathname to filetaranis.com
would precede all of its package names withcom.taranis
. Each component of the package name corresponds to a subdirectory. So, if Taranis had agraphics
package that contained aRectangle.java
source file, it would be contained in a series of subdirectories, as shown here:When you compile a source file, the compiler creates a different output file for each class and interface defined in it. The basename of the output file is the name of the class or interface, and its extension is .class
:Like a
This figure has been reduced to fit on the page.
Click the image to view it at its natural size..java
file, a.class
file should also be in a series of directories that reflect the package name. However, it does not have to be in the same directory as its source. You could arrange your source and class directories separately, like this:By doing this, you can give the classes directory to other programmers without revealing your sources. Why all the bother about directories and filenames? You need to manage your source and class files in this manner so that the compiler and the interpreter can find all of the classes and interfaces used by your program. When the compiler encounters a new class as it's compiling your program, it must be able to find the class so as to resolve names, do type checking, and so on. Similarly, when the interpreter encounters a new class as it's running your program, it must be able to find the class to invoke its methods, and so on. Both the compiler and the interpreter search for classes in each directory or zip file listed in your class path.
Definition: A class path is a list of directories or zip files to search for class files.Each directory listed in the class path is a top-level directory in which package directories appear. From the top-level directory, the compiler and the interpreter can construct the rest of the path based on the package and class name for the class. For example, the class path entry for the directory structure shown in the previous diagram page would include
classes
, but notcom
or any of the directories belowcom
. Both the compiler and the interpreter construct the path name to a.class
file with its full package name.By default, the compiler and the interpreter search the current directory and the zip file containing the JDK class files. In other words, the current directory and the JDK class files are automatically in your class path. Most, if not all, classes can be found in these two locations. So it's likely that you don't have to worry about your class path. In some cases, however, you may have to set your class path.
If you must, you can change your class path. This can be done in either of two ways:We don't recommend setting the
- Set the
CLASSPATH
environment variable (not recommended).- Use the
-classpath
runtime option when you invoke the compiler or the interpreter.CLASSPATH
environment variable because it can be long-lived (particularly if you set it in a login or startup script). It's also easy to forget about, and then one day, your programs won't work because the compiler or interpreter loads a crusty old class file instead of the one you want. An old, out-of-dateCLASSPATH
variable is a fruitful source of confusing problems.The second option, setting the class path with the runtime option, is preferable because it sets the class path only for the current invocation of the compiler or the interpreter. Here's how to use the runtime option
-classpath
to set your class path.
Platform-specific Details: Using the -classpath Runtime Option:UNIX:
DOS shell (Windows 95/NT):javac -classpath .:~/classes:/JDK/lib/classes.zipjavac -classpath .;C:\classes;C:\JDK\lib\classes.zipWhen you specify a class path in this manner, you completely override the current class path. Thus you must include the
classes.zip
file from the JDK in the class path. It's a good idea to include the current directory as well.The order of the entries in the class path is important. When the Java interpreter is looking for a class, it searches the entries in your class path, in order, until it finds a class with the correct name. The Java interpreter runs the first class with the correct name that it encounters and does not search the remaining entries.
Note: If you load an applet into a Java application such as HotJava or the Applet Viewer and the loaded class is in the class path, the applet doesn't have the restrictions that applets loaded over the network do, so it can never be reloaded. We recommend never starting an application such as HotJava in the same directory as an Applet class because the current directory "." is usually part of the class path.
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