[Accessor]
first
list => object
(setf (first
list) new-object)
second
list => object
(setf (second
list) new-object)
third
list => object
(setf (third
list) new-object)
fourth
list => object
(setf (fourth
list) new-object)
fifth
list => object
(setf (fifth
list) new-object)
sixth
list => object
(setf (sixth
list) new-object)
seventh
list => object
(setf (seventh
list) new-object)
eighth
list => object
(setf (eighth
list) new-object)
ninth
list => object
(setf (ninth
list) new-object)
tenth
list => object
(setf (tenth
list) new-object)
list---a list,
which might be a dotted list or a circular list.
object, new-object---an object.
The functions first, second, third, fourth, fifth, sixth, seventh, eighth, ninth, and tenth access the first, second, third, fourth, fifth, sixth, seventh, eighth, ninth, and tenth elements of list, respectively. Specifically,
(first list) == (car list) (second list) == (car (cdr list)) (third list) == (car (cddr list)) (fourth list) == (car (cdddr list)) (fifth list) == (car (cddddr list)) (sixth list) == (car (cdr (cddddr list))) (seventh list) == (car (cddr (cddddr list))) (eighth list) == (car (cdddr (cddddr list))) (ninth list) == (car (cddddr (cddddr list))) (tenth list) == (car (cdr (cddddr (cddddr list))))
setf can also be used with any of these functions to change an existing component. The same equivalences apply. For example:
(setf (fifth list) new-object) == (setf (car (cddddr list)) new-object)
(setq lst '(1 2 3 (4 5 6) ((V)) vi 7 8 9 10)) => (1 2 3 (4 5 6) ((V)) VI 7 8 9 10) (first lst) => 1 (tenth lst) => 10 (fifth lst) => ((V)) (second (fourth lst)) => 5 (sixth '(1 2 3)) => NIL (setf (fourth lst) "four") => "four" lst => (1 2 3 "four" ((V)) VI 7 8 9 10)
@xref{car; cdr; caar; cadr; cdar; cddr; caaar; caadr; cadar; caddr; cdaar; cdadr; cddar; cdddr; caaaar; caaadr; caadar; caaddr; cadaar; cadadr; caddar; cadddr; cdaaar; cdaadr; cdadar; cdaddr; cddaar; cddadr; cdddar; cddddr} , section nth [Accessor]
first is functionally equivalent to car, second is functionally equivalent to cadr, third is functionally equivalent to caddr, and fourth is functionally equivalent to cadddr.
The ordinal numbering used here is one-origin, as opposed to the zero-origin numbering used by nth:
(fifth x) == (nth 4 x)
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